12+3x=3x-3(2x+6)

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Solution for 12+3x=3x-3(2x+6) equation: 



12+3x=3x-3(2x+6)

We move all terms to the left:

12+3x-(3x-3(2x+6))=0



We calculate terms in parentheses: -(3x-3(2x+6)), so:

3x-3(2x+6)

We multiply parentheses

3x-6x-18

We add all the numbers together, and all the variables

-3x-18

Back to the equation:

-(-3x-18)



We get rid of parentheses

3x+3x+18+12=0

We add all the numbers together, and all the variables

6x+30=0

We move all terms containing x to the left, all other terms to the right

6x=-30

x=-30/6

x=-5

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