8=(3x-18)+(x-2)

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Solution for 8=(3x-18)+(x-2) equation: 



8=(3x-18)+(x-2)

We move all terms to the left:

8-((3x-18)+(x-2))=0



We calculate terms in parentheses: -((3x-18)+(x-2)), so:

(3x-18)+(x-2)

We get rid of parentheses

3x+x-18-2

We add all the numbers together, and all the variables

4x-20

Back to the equation:

-(4x-20)



We get rid of parentheses

-4x+20+8=0

We add all the numbers together, and all the variables

-4x+28=0

We move all terms containing x to the left, all other terms to the right

-4x=-28

x=-28/-4

x=+7

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