13=(4x-12)+(x+5)

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Solution for 13=(4x-12)+(x+5) equation: 



13=(4x-12)+(x+5)

We move all terms to the left:

13-((4x-12)+(x+5))=0



We calculate terms in parentheses: -((4x-12)+(x+5)), so:

(4x-12)+(x+5)

We get rid of parentheses

4x+x-12+5

We add all the numbers together, and all the variables

5x-7

Back to the equation:

-(5x-7)



We get rid of parentheses

-5x+7+13=0

We add all the numbers together, and all the variables

-5x+20=0

We move all terms containing x to the left, all other terms to the right

-5x=-20

x=-20/-5

x=+4

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