6(m-1)-4=7(1+m)-4

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Solution for 6(m-1)-4=7(1+m)-4 equation:



6(m-1)-4=7(1+m)-4
We move all terms to the left:
6(m-1)-4-(7(1+m)-4)=0
We add all the numbers together, and all the variables
6(m-1)-(7(m+1)-4)-4=0
We multiply parentheses
6m-(7(m+1)-4)-6-4=0
We calculate terms in parentheses: -(7(m+1)-4), so:
7(m+1)-4
We multiply parentheses
7m+7-4
We add all the numbers together, and all the variables
7m+3
Back to the equation:
-(7m+3)
We add all the numbers together, and all the variables
6m-(7m+3)-10=0
We get rid of parentheses
6m-7m-3-10=0
We add all the numbers together, and all the variables
-1m-13=0
We move all terms containing m to the left, all other terms to the right
-m=13
m=13/-1
m=-13

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