8=(3/4)x+12-x+4

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Solution for 8=(3/4)x+12-x+4 equation:



8=(3/4)x+12-x+4
We move all terms to the left:
8-((3/4)x+12-x+4)=0
Domain of the equation: 4)x+12-x+4)!=0
x!=0/1
x!=0
x∈R
We add all the numbers together, and all the variables
-((+3/4)x+12-x+4)+8=0
We multiply all the terms by the denominator
-((+3+8*4)x+12-x+4)=0
We calculate terms in parentheses: -((+3+8*4)x+12-x+4), so:
(+3+8*4)x+12-x+4
determiningTheFunctionDomain (+3+8*4)x-x+12+4
We add all the numbers together, and all the variables
35x-x+12+4
We add all the numbers together, and all the variables
34x+16
Back to the equation:
-(34x+16)
We get rid of parentheses
-34x-16=0
We move all terms containing x to the left, all other terms to the right
-34x=16
x=16/-34
x=-8/17

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