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5y+4-3y=2(y+6)-8
We move all terms to the left:
5y+4-3y-(2(y+6)-8)=0
We add all the numbers together, and all the variables
2y-(2(y+6)-8)+4=0
We calculate terms in parentheses: -(2(y+6)-8), so:We get rid of parentheses
2(y+6)-8
We multiply parentheses
2y+12-8
We add all the numbers together, and all the variables
2y+4
Back to the equation:
-(2y+4)
2y-2y-4+4=0
We add all the numbers together, and all the variables
=0
y=0/1
y=0
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