4x+3(x+2)+(x+4)=0

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Solution for 4x+3(x+2)+(x+4)=0 equation: 



4x+3(x+2)+(x+4)=0

We multiply parentheses

4x+3x+(x+4)+6=0

We get rid of parentheses

4x+3x+x+4+6=0

We add all the numbers together, and all the variables

8x+10=0

We move all terms containing x to the left, all other terms to the right

8x=-10

x=-10/8

x=-1+1/4

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