3=-7(n-4)+8(1+5n)

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Solution for 3=-7(n-4)+8(1+5n) equation: 



3=-7(n-4)+8(1+5n)

We move all terms to the left:

3-(-7(n-4)+8(1+5n))=0

We add all the numbers together, and all the variables

-(-7(n-4)+8(5n+1))+3=0



We calculate terms in parentheses: -(-7(n-4)+8(5n+1)), so:

-7(n-4)+8(5n+1)

We multiply parentheses

-7n+40n+28+8

We add all the numbers together, and all the variables

33n+36

Back to the equation:

-(33n+36)



We get rid of parentheses

-33n-36+3=0

We add all the numbers together, and all the variables

-33n-33=0

We move all terms containing n to the left, all other terms to the right

-33n=33

n=33/-33

n=-1

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