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8=(10+2)/t
We move all terms to the left:
8-((10+2)/t)=0
Domain of the equation: t)!=0We add all the numbers together, and all the variables
t!=0/1
t!=0
t∈R
-(12/t)+8=0
We get rid of parentheses
-12/t+8=0
We multiply all the terms by the denominator
8*t-12=0
We add all the numbers together, and all the variables
8t-12=0
We move all terms containing t to the left, all other terms to the right
8t=12
t=12/8
t=1+1/2
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