5(v+2)+3(v+4)=1

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Solution for 5(v+2)+3(v+4)=1 equation: 



5(v+2)+3(v+4)=1

We move all terms to the left:

5(v+2)+3(v+4)-(1)=0

We multiply parentheses

5v+3v+10+12-1=0

We add all the numbers together, and all the variables

8v+21=0

We move all terms containing v to the left, all other terms to the right

8v=-21

v=-21/8

v=-2+5/8

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