5(x-3)-(x-2)=5(x+1)-1

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Solution for 5(x-3)-(x-2)=5(x+1)-1 equation: 



5(x-3)-(x-2)=5(x+1)-1

We move all terms to the left:

5(x-3)-(x-2)-(5(x+1)-1)=0

We multiply parentheses

5x-(x-2)-(5(x+1)-1)-15=0

We get rid of parentheses

5x-x-(5(x+1)-1)+2-15=0



We calculate terms in parentheses: -(5(x+1)-1), so:

5(x+1)-1

We multiply parentheses

5x+5-1

We add all the numbers together, and all the variables

5x+4

Back to the equation:

-(5x+4)



We add all the numbers together, and all the variables

4x-(5x+4)-13=0

We get rid of parentheses

4x-5x-4-13=0

We add all the numbers together, and all the variables

-1x-17=0

We move all terms containing x to the left, all other terms to the right

-x=17

x=17/-1

x=-17

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