3(2q+12)=-2q-68

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Solution for 3(2q+12)=-2q-68 equation: 



3(2q+12)=-2q-68

We move all terms to the left:

3(2q+12)-(-2q-68)=0

We multiply parentheses

6q-(-2q-68)+36=0

We get rid of parentheses

6q+2q+68+36=0

We add all the numbers together, and all the variables

8q+104=0

We move all terms containing q to the left, all other terms to the right

8q=-104

q=-104/8

q=-13

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