88=w(2w+5)

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Solution for 88=w(2w+5) equation:



88=w(2w+5)
We move all terms to the left:
88-(w(2w+5))=0
We calculate terms in parentheses: -(w(2w+5)), so:
w(2w+5)
We multiply parentheses
2w^2+5w
Back to the equation:
-(2w^2+5w)
We get rid of parentheses
-2w^2-5w+88=0
a = -2; b = -5; c = +88;
Δ = b2-4ac
Δ = -52-4·(-2)·88
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{729}=27$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-27}{2*-2}=\frac{-22}{-4} =5+1/2 $
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+27}{2*-2}=\frac{32}{-4} =-8 $

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