10=5(7r+3)-5(r-5)

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Solution for 10=5(7r+3)-5(r-5) equation: 



10=5(7r+3)-5(r-5)

We move all terms to the left:

10-(5(7r+3)-5(r-5))=0



We calculate terms in parentheses: -(5(7r+3)-5(r-5)), so:

5(7r+3)-5(r-5)

We multiply parentheses

35r-5r+15+25

We add all the numbers together, and all the variables

30r+40

Back to the equation:

-(30r+40)



We get rid of parentheses

-30r-40+10=0

We add all the numbers together, and all the variables

-30r-30=0

We move all terms containing r to the left, all other terms to the right

-30r=30

r=30/-30

r=-1

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