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8-2(3-x)=4x-2(x-1)
We move all terms to the left:
8-2(3-x)-(4x-2(x-1))=0
We add all the numbers together, and all the variables
-2(-1x+3)-(4x-2(x-1))+8=0
We multiply parentheses
2x-(4x-2(x-1))-6+8=0
We calculate terms in parentheses: -(4x-2(x-1)), so:We add all the numbers together, and all the variables
4x-2(x-1)
We multiply parentheses
4x-2x+2
We add all the numbers together, and all the variables
2x+2
Back to the equation:
-(2x+2)
2x-(2x+2)+2=0
We get rid of parentheses
2x-2x-2+2=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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