2+3(x-2)=2-5(x-5)

Solution for 2+3(x-2)=2-5(x-5) equation:

2+3(x-2)=2-5(x-5)

We move all terms to the left:

2+3(x-2)-(2-5(x-5))=0

We multiply parentheses

3x-(2-5(x-5))-6+2=0


We calculate terms in parentheses: -(2-5(x-5)), so:

2-5(x-5)

determiningTheFunctionDomain
-5(x-5)+2

We multiply parentheses

-5x+25+2

We add all the numbers together, and all the variables

-5x+27

Back to the equation:

-(-5x+27)


We add all the numbers together, and all the variables

3x-(-5x+27)-4=0

We get rid of parentheses

3x+5x-27-4=0

We add all the numbers together, and all the variables

8x-31=0

We move all terms containing x to the left, all other terms to the right

8x=31

x=31/8

x=3+7/8