-2(x-2)-4x=3(x+1)-x

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Solution for -2(x-2)-4x=3(x+1)-x equation: 



-2(x-2)-4x=3(x+1)-x

We move all terms to the left:

-2(x-2)-4x-(3(x+1)-x)=0

We add all the numbers together, and all the variables

-4x-2(x-2)-(3(x+1)-x)=0

We multiply parentheses

-4x-2x-(3(x+1)-x)+4=0



We calculate terms in parentheses: -(3(x+1)-x), so:

3(x+1)-x

We add all the numbers together, and all the variables

-1x+3(x+1)

We multiply parentheses

-1x+3x+3

We add all the numbers together, and all the variables

2x+3

Back to the equation:

-(2x+3)



We add all the numbers together, and all the variables

-6x-(2x+3)+4=0

We get rid of parentheses

-6x-2x-3+4=0

We add all the numbers together, and all the variables

-8x+1=0

We move all terms containing x to the left, all other terms to the right

-8x=-1

x=-1/-8

x=1/8

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