8(z+3)=4(z+2)-20

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Solution for 8(z+3)=4(z+2)-20 equation: 



8(z+3)=4(z+2)-20

We move all terms to the left:

8(z+3)-(4(z+2)-20)=0

We multiply parentheses

8z-(4(z+2)-20)+24=0



We calculate terms in parentheses: -(4(z+2)-20), so:

4(z+2)-20

We multiply parentheses

4z+8-20

We add all the numbers together, and all the variables

4z-12

Back to the equation:

-(4z-12)



We get rid of parentheses

8z-4z+12+24=0

We add all the numbers together, and all the variables

4z+36=0

We move all terms containing z to the left, all other terms to the right

4z=-36

z=-36/4

z=-9

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