40-4x=-5(4x+3)-5(-8-3x)

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Solution for 40-4x=-5(4x+3)-5(-8-3x) equation: 



40-4x=-5(4x+3)-5(-8-3x)

We move all terms to the left:

40-4x-(-5(4x+3)-5(-8-3x))=0

We add all the numbers together, and all the variables

-4x-(-5(4x+3)-5(-3x-8))+40=0



We calculate terms in parentheses: -(-5(4x+3)-5(-3x-8)), so:

-5(4x+3)-5(-3x-8)

We multiply parentheses

-20x+15x-15+40

We add all the numbers together, and all the variables

-5x+25

Back to the equation:

-(-5x+25)



We get rid of parentheses

-4x+5x-25+40=0

We add all the numbers together, and all the variables

x+15=0

We move all terms containing x to the left, all other terms to the right

x=-15

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