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67=(9/5)x+32
We move all terms to the left:
67-((9/5)x+32)=0
Domain of the equation: 5)x+32)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
-((+9/5)x+32)+67=0
We multiply all the terms by the denominator
-((+9+67*5)x+32)=0
We calculate terms in parentheses: -((+9+67*5)x+32), so:We get rid of parentheses
(+9+67*5)x+32
We add all the numbers together, and all the variables
344x+32
Back to the equation:
-(344x+32)
-344x-32=0
We move all terms containing x to the left, all other terms to the right
-344x=32
x=32/-344
x=-4/43
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