1/3(x-5)+5/6(x+2)=x+1

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Solution for 1/3(x-5)+5/6(x+2)=x+1 equation: 



1/3(x-5)+5/6(x+2)=x+1

We move all terms to the left:

1/3(x-5)+5/6(x+2)-(x+1)=0



Domain of the equation: 3(x-5)!=0

x∈R





Domain of the equation: 6(x+2)!=0

x∈R



We get rid of parentheses

1/3(x-5)+5/6(x+2)-x-1=0

We calculate fractions


-x+(6xx/(3(x-5)*6(x+2))+(15xx/(3(x-5)*6(x+2))-1=0

We can not solve this equation

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