8(y-1)-4=(2y-3)

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Solution for 8(y-1)-4=(2y-3) equation: 



8(y-1)-4=(2y-3)

We move all terms to the left:

8(y-1)-4-((2y-3))=0

We multiply parentheses

8y-((2y-3))-8-4=0



We calculate terms in parentheses: -((2y-3)), so:

(2y-3)

We get rid of parentheses

2y-3

Back to the equation:

-(2y-3)



We add all the numbers together, and all the variables

8y-(2y-3)-12=0

We get rid of parentheses

8y-2y+3-12=0

We add all the numbers together, and all the variables

6y-9=0

We move all terms containing y to the left, all other terms to the right

6y=9

y=9/6

y=1+1/2

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