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(1/4)(3x+4)+x=-5(1/4x-8)
We move all terms to the left:
(1/4)(3x+4)+x-(-5(1/4x-8))=0
Domain of the equation: 4)(3x+4)!=0
x∈R
Domain of the equation: 4x-8))!=0We add all the numbers together, and all the variables
x∈R
(+1/4)(3x+4)+x-(-5(1/4x-8))=0
We add all the numbers together, and all the variables
x+(+1/4)(3x+4)-(-5(1/4x-8))=0
We multiply parentheses ..
(+3x^2+1/4*4)+x-(-5(1/4x-8))=0
We calculate fractions
x+(3x^2+4x)/64x^2+()/64x^2=0
We multiply all the terms by the denominator
x*64x^2+(3x^2+4x)+()=0
We add all the numbers together, and all the variables
x*64x^2+(3x^2+4x)=0
Wy multiply elements
64x^3+(3x^2+4x)=0
We get rid of parentheses
64x^3+3x^2+4x=0
We do not support expression: x^3
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