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4x+1/2(8x+6)=2(2x+3)
We move all terms to the left:
4x+1/2(8x+6)-(2(2x+3))=0
Domain of the equation: 2(8x+6)!=0We multiply all the terms by the denominator
x∈R
4x*2(8x+6)-((2(2x+3)))*2(8x+6)+1=0
We calculate terms in parentheses: -((2(2x+3)))*2(8x+6), so:Wy multiply elements
(2(2x+3)))*2(8x+6
8x^2(8-((2(2x+3)))*2(8x+6)+1=0
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