8(y+2)=48y

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Solution for 8(y+2)=48y equation: 



8(y+2)=48y

We move all terms to the left:

8(y+2)-(48y)=0

We add all the numbers together, and all the variables

-48y+8(y+2)=0

We multiply parentheses

-48y+8y+16=0

We add all the numbers together, and all the variables

-40y+16=0

We move all terms containing y to the left, all other terms to the right

-40y=-16

y=-16/-40

y=2/5

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