7x2-36x-12=0

Solution for 7x2-36x-12=0 equation:

7x^2-36x-12=0

a = 7; b = -36; c = -12;
Δ = b2-4ac
Δ = -362-4·7·(-12)
Δ = 1632
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1632}=\sqrt{16*102}=\sqrt{16}*\sqrt{102}=4\sqrt{102}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-4\sqrt{102}}{2*7}=\frac{36-4\sqrt{102}}{14}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+4\sqrt{102}}{2*7}=\frac{36+4\sqrt{102}}{14}
$