7(3x-1)-6(2x+3)=8(x-2)+2

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Solution for 7(3x-1)-6(2x+3)=8(x-2)+2 equation: 



7(3x-1)-6(2x+3)=8(x-2)+2

We move all terms to the left:

7(3x-1)-6(2x+3)-(8(x-2)+2)=0

We multiply parentheses

21x-12x-(8(x-2)+2)-7-18=0



We calculate terms in parentheses: -(8(x-2)+2), so:

8(x-2)+2

We multiply parentheses

8x-16+2

We add all the numbers together, and all the variables

8x-14

Back to the equation:

-(8x-14)



We add all the numbers together, and all the variables

9x-(8x-14)-25=0

We get rid of parentheses

9x-8x+14-25=0

We add all the numbers together, and all the variables

x-11=0

We move all terms containing x to the left, all other terms to the right

x=11

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