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8(x-5)+3=1+7x
We move all terms to the left:
8(x-5)+3-(1+7x)=0
We add all the numbers together, and all the variables
8(x-5)-(7x+1)+3=0
We multiply parentheses
8x-(7x+1)-40+3=0
We get rid of parentheses
8x-7x-1-40+3=0
We add all the numbers together, and all the variables
x-38=0
We move all terms containing x to the left, all other terms to the right
x=38
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