-(x-2)+x=6(x+3)-4x

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Solution for -(x-2)+x=6(x+3)-4x equation: 



-(x-2)+x=6(x+3)-4x

We move all terms to the left:

-(x-2)+x-(6(x+3)-4x)=0

We add all the numbers together, and all the variables

x-(x-2)-(6(x+3)-4x)=0

We get rid of parentheses

x-x-(6(x+3)-4x)+2=0



We calculate terms in parentheses: -(6(x+3)-4x), so:

6(x+3)-4x

We add all the numbers together, and all the variables

-4x+6(x+3)

We multiply parentheses

-4x+6x+18

We add all the numbers together, and all the variables

2x+18

Back to the equation:

-(2x+18)



We add all the numbers together, and all the variables

-(2x+18)+2=0

We get rid of parentheses

-2x-18+2=0

We add all the numbers together, and all the variables

-2x-16=0

We move all terms containing x to the left, all other terms to the right

-2x=16

x=16/-2

x=-8

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