3/4(x+20)=1/2(x-2)

Solution for 3/4(x+20)=1/2(x-2) equation:

3/4(x+20)=1/2(x-2)

We move all terms to the left:

3/4(x+20)-(1/2(x-2))=0


Domain of the equation: 4(x+20)!=0

x∈R



Domain of the equation: 2(x-2))!=0

x∈R


We calculate fractions


(6xx/(4(x+20)*2(x-2)))+(-4xx/(4(x+20)*2(x-2)))=0


We calculate terms in parentheses: +(6xx/(4(x+20)*2(x-2))), so:

6xx/(4(x+20)*2(x-2))

We multiply all the terms by the denominator


6xx

Back to the equation:

+(6xx)



We calculate terms in parentheses: +(-4xx/(4(x+20)*2(x-2))), so:

-4xx/(4(x+20)*2(x-2))

We multiply all the terms by the denominator


-4xx

Back to the equation:

+(-4xx)


We get rid of parentheses

6xx-4xx=0