8(x+2)=4(4x-2)

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Solution for 8(x+2)=4(4x-2) equation: 



8(x+2)=4(4x-2)

We move all terms to the left:

8(x+2)-(4(4x-2))=0

We multiply parentheses

8x-(4(4x-2))+16=0



We calculate terms in parentheses: -(4(4x-2)), so:

4(4x-2)

We multiply parentheses

16x-8

Back to the equation:

-(16x-8)



We get rid of parentheses

8x-16x+8+16=0

We add all the numbers together, and all the variables

-8x+24=0

We move all terms containing x to the left, all other terms to the right

-8x=-24

x=-24/-8

x=+3

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