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x2-15x+8=0
We add all the numbers together, and all the variables
x^2-15x+8=0
a = 1; b = -15; c = +8;
Δ = b2-4ac
Δ = -152-4·1·8
Δ = 193
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-\sqrt{193}}{2*1}=\frac{15-\sqrt{193}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+\sqrt{193}}{2*1}=\frac{15+\sqrt{193}}{2} $
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