8(x+2)-3x=6X2

Solution for 8(x+2)-3x=6X2 equation:

8(x+2)-3x=6x^2

We move all terms to the left:

8(x+2)-3x-(6x^2)=0

determiningTheFunctionDomain
-6x^2+8(x+2)-3x=0

We add all the numbers together, and all the variables

-6x^2-3x+8(x+2)=0

We multiply parentheses

-6x^2-3x+8x+16=0

We add all the numbers together, and all the variables

-6x^2+5x+16=0

a = -6; b = 5; c = +16;
Δ = b2-4ac
Δ = 52-4·(-6)·16
Δ = 409
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{409}}{2*-6}=\frac{-5-\sqrt{409}}{-12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{409}}{2*-6}=\frac{-5+\sqrt{409}}{-12}
$