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4/9x+1/5x=59
We move all terms to the left:
4/9x+1/5x-(59)=0
Domain of the equation: 9x!=0
x!=0/9
x!=0
x∈R
Domain of the equation: 5x!=0We calculate fractions
x!=0/5
x!=0
x∈R
20x/45x^2+9x/45x^2-59=0
We multiply all the terms by the denominator
20x+9x-59*45x^2=0
We add all the numbers together, and all the variables
29x-59*45x^2=0
Wy multiply elements
-2655x^2+29x=0
a = -2655; b = 29; c = 0;
Δ = b2-4ac
Δ = 292-4·(-2655)·0
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{841}=29$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-29}{2*-2655}=\frac{-58}{-5310} =29/2655 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+29}{2*-2655}=\frac{0}{-5310} =0 $
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