2/3x-11=4/5x+5

Solution for 2/3x-11=4/5x+5 equation:

2/3x-11=4/5x+5

We move all terms to the left:

2/3x-11-(4/5x+5)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R



Domain of the equation: 5x+5)!=0

x∈R


We get rid of parentheses

2/3x-4/5x-5-11=0

We calculate fractions


10x/15x^2+(-12x)/15x^2-5-11=0

We add all the numbers together, and all the variables

10x/15x^2+(-12x)/15x^2-16=0

We multiply all the terms by the denominator


10x+(-12x)-16*15x^2=0

Wy multiply elements

-240x^2+10x+(-12x)=0

We get rid of parentheses

-240x^2+10x-12x=0

We add all the numbers together, and all the variables

-240x^2-2x=0

a = -240; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·(-240)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*-240}=\frac{0}{-480}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*-240}=\frac{4}{-480}
=-1/120
$