8(x+1)=3(4x)+12

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Solution for 8(x+1)=3(4x)+12 equation: 



8(x+1)=3(4x)+12

We move all terms to the left:

8(x+1)-(3(4x)+12)=0

We multiply parentheses

8x-(34x+12)+8=0

We get rid of parentheses

8x-34x-12+8=0

We add all the numbers together, and all the variables

-26x-4=0

We move all terms containing x to the left, all other terms to the right

-26x=4

x=4/-26

x=-2/13

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