x2-36x+36=0

Solution for x2-36x+36=0 equation:

x2-36x+36=0

We add all the numbers together, and all the variables

x^2-36x+36=0

a = 1; b = -36; c = +36;
Δ = b2-4ac
Δ = -362-4·1·36
Δ = 1152
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1152}=\sqrt{576*2}=\sqrt{576}*\sqrt{2}=24\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-24\sqrt{2}}{2*1}=\frac{36-24\sqrt{2}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+24\sqrt{2}}{2*1}=\frac{36+24\sqrt{2}}{2}
$