5(6-10x)=-10(-10-2x)

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Solution for 5(6-10x)=-10(-10-2x) equation: 



5(6-10x)=-10(-10-2x)

We move all terms to the left:

5(6-10x)-(-10(-10-2x))=0

We add all the numbers together, and all the variables

5(-10x+6)-(-10(-2x-10))=0

We multiply parentheses

-50x-(-10(-2x-10))+30=0



We calculate terms in parentheses: -(-10(-2x-10)), so:

-10(-2x-10)

We multiply parentheses

20x+100

Back to the equation:

-(20x+100)



We get rid of parentheses

-50x-20x-100+30=0

We add all the numbers together, and all the variables

-70x-70=0

We move all terms containing x to the left, all other terms to the right

-70x=70

x=70/-70

x=-1

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