8(x+1)(x-1)=4x(x+1)+27

Solution for 8(x+1)(x-1)=4x(x+1)+27 equation:

8(x+1)(x-1)=4x(x+1)+27

We move all terms to the left:

8(x+1)(x-1)-(4x(x+1)+27)=0

We use the square of the difference formula

x^2-(4x(x+1)+27)-1=0


We calculate terms in parentheses: -(4x(x+1)+27), so:

4x(x+1)+27

We multiply parentheses

4x^2+4x+27

Back to the equation:

-(4x^2+4x+27)


We get rid of parentheses

x^2-4x^2-4x-27-1=0

We add all the numbers together, and all the variables

-3x^2-4x-28=0

a = -3; b = -4; c = -28;
Δ = b2-4ac
Δ = -42-4·(-3)·(-28)
Δ = -320
Delta is less than zero, so there is no solution for the equation