4Y+8X=40z

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Solution for 4Y+8X=40z equation: 



4+8Y=40Y

We move all terms to the left:

4+8Y-(40Y)=0

We add all the numbers together, and all the variables

-32Y+4=0

We move all terms containing Y to the left, all other terms to the right

-32Y=-4

Y=-4/-32

Y=1/8

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