3(x-2)-5(1-x)=1-4(3-2x)

Solution for 3(x-2)-5(1-x)=1-4(3-2x) equation:

3(x-2)-5(1-x)=1-4(3-2x)

We move all terms to the left:

3(x-2)-5(1-x)-(1-4(3-2x))=0

We add all the numbers together, and all the variables

3(x-2)-5(-1x+1)-(1-4(-2x+3))=0

We multiply parentheses

3x+5x-(1-4(-2x+3))-6-5=0


We calculate terms in parentheses: -(1-4(-2x+3)), so:

1-4(-2x+3)

determiningTheFunctionDomain
-4(-2x+3)+1

We multiply parentheses

8x-12+1

We add all the numbers together, and all the variables

8x-11

Back to the equation:

-(8x-11)


We add all the numbers together, and all the variables

8x-(8x-11)-11=0

We get rid of parentheses

8x-8x+11-11=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0