8(t+2)-3(t-4)-4)=6(t-7)+8=

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Solution for 8(t+2)-3(t-4)-4)=6(t-7)+8= equation: 



8(t+2)-3(t-4)-4)=6(t-7)+8=

We move all terms to the left:

8(t+2)-3(t-4)-4)-(6(t-7)+8)=0

We add all the numbers together, and all the variables

8(t+2)-3(t-4)-4)-(6(t-7)=0

We multiply parentheses

8t-3t-4)-(6(t-7)+16+12=0

We add all the numbers together, and all the variables

5t-4)-(6(t-7)+28=0

We move all terms containing t to the left, all other terms to the right

5t-4)-(6(t-7)=-28

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