16=2(u-4)+6u

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Solution for 16=2(u-4)+6u equation: 



16=2(u-4)+6u

We move all terms to the left:

16-(2(u-4)+6u)=0



We calculate terms in parentheses: -(2(u-4)+6u), so:

2(u-4)+6u

We add all the numbers together, and all the variables

6u+2(u-4)

We multiply parentheses

6u+2u-8

We add all the numbers together, and all the variables

8u-8

Back to the equation:

-(8u-8)



We get rid of parentheses

-8u+8+16=0

We add all the numbers together, and all the variables

-8u+24=0

We move all terms containing u to the left, all other terms to the right

-8u=-24

u=-24/-8

u=+3

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