8(s-3)-3=4(s+2)+13

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Solution for 8(s-3)-3=4(s+2)+13 equation: 



8(s-3)-3=4(s+2)+13

We move all terms to the left:

8(s-3)-3-(4(s+2)+13)=0

We multiply parentheses

8s-(4(s+2)+13)-24-3=0



We calculate terms in parentheses: -(4(s+2)+13), so:

4(s+2)+13

We multiply parentheses

4s+8+13

We add all the numbers together, and all the variables

4s+21

Back to the equation:

-(4s+21)



We add all the numbers together, and all the variables

8s-(4s+21)-27=0

We get rid of parentheses

8s-4s-21-27=0

We add all the numbers together, and all the variables

4s-48=0

We move all terms containing s to the left, all other terms to the right

4s=48

s=48/4

s=12

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