6(c+2)-4=5(c+2)

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Solution for 6(c+2)-4=5(c+2) equation: 



6(c+2)-4=5(c+2)

We move all terms to the left:

6(c+2)-4-(5(c+2))=0

We multiply parentheses

6c-(5(c+2))+12-4=0



We calculate terms in parentheses: -(5(c+2)), so:

5(c+2)

We multiply parentheses

5c+10

Back to the equation:

-(5c+10)



We add all the numbers together, and all the variables

6c-(5c+10)+8=0

We get rid of parentheses

6c-5c-10+8=0

We add all the numbers together, and all the variables

c-2=0

We move all terms containing c to the left, all other terms to the right

c=2

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