8(b-1)+9=4-(b-5)

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Solution for 8(b-1)+9=4-(b-5) equation: 



8(b-1)+9=4-(b-5)

We move all terms to the left:

8(b-1)+9-(4-(b-5))=0

We multiply parentheses

8b-(4-(b-5))-8+9=0



We calculate terms in parentheses: -(4-(b-5)), so:

4-(b-5)

determiningTheFunctionDomain
-(b-5)+4

We get rid of parentheses

-b+5+4

We add all the numbers together, and all the variables

-1b+9

Back to the equation:

-(-1b+9)



We add all the numbers together, and all the variables

8b-(-1b+9)+1=0

We get rid of parentheses

8b+1b-9+1=0

We add all the numbers together, and all the variables

9b-8=0

We move all terms containing b to the left, all other terms to the right

9b=8

b=8/9

b=8/9

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