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x=2x(81-x)
We move all terms to the left:
x-(2x(81-x))=0
We add all the numbers together, and all the variables
x-(2x(-1x+81))=0
We calculate terms in parentheses: -(2x(-1x+81)), so:We get rid of parentheses
2x(-1x+81)
We multiply parentheses
-2x^2+162x
Back to the equation:
-(-2x^2+162x)
2x^2-162x+x=0
We add all the numbers together, and all the variables
2x^2-161x=0
a = 2; b = -161; c = 0;
Δ = b2-4ac
Δ = -1612-4·2·0
Δ = 25921
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25921}=161$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-161)-161}{2*2}=\frac{0}{4} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-161)+161}{2*2}=\frac{322}{4} =80+1/2 $
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