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(1/x)=(5/200)
We move all terms to the left:
(1/x)-((5/200))=0
Domain of the equation: x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+1/x)-((+5/200))=0
We get rid of parentheses
1/x-((+5/200))=0
We calculate fractions
()/200x^2+(-((+5*x)/200x^2=0
We add all the numbers together, and all the variables
()/200x^2+(-((+5x)/200x^2=0
We multiply all the terms by the denominator
(-((+5x)+()=0
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