8(5y-10)+20=30y

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Solution for 8(5y-10)+20=30y equation: 



8(5y-10)+20=30y

We move all terms to the left:

8(5y-10)+20-(30y)=0

We add all the numbers together, and all the variables

-30y+8(5y-10)+20=0

We multiply parentheses

-30y+40y-80+20=0

We add all the numbers together, and all the variables

10y-60=0

We move all terms containing y to the left, all other terms to the right

10y=60

y=60/10

y=6

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