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1/2a-2=3/5a+4
We move all terms to the left:
1/2a-2-(3/5a+4)=0
Domain of the equation: 2a!=0
a!=0/2
a!=0
a∈R
Domain of the equation: 5a+4)!=0We get rid of parentheses
a∈R
1/2a-3/5a-4-2=0
We calculate fractions
5a/10a^2+(-6a)/10a^2-4-2=0
We add all the numbers together, and all the variables
5a/10a^2+(-6a)/10a^2-6=0
We multiply all the terms by the denominator
5a+(-6a)-6*10a^2=0
Wy multiply elements
-60a^2+5a+(-6a)=0
We get rid of parentheses
-60a^2+5a-6a=0
We add all the numbers together, and all the variables
-60a^2-1a=0
a = -60; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·(-60)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*-60}=\frac{0}{-120} =0 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*-60}=\frac{2}{-120} =-1/60 $
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